WebFeb 19, 2024 · I figured out the solution: turn it into a number of a type string and use the destring command. replace q1="1" if q1=="Female" destring q1, replace Share Improve this answer Follow edited Feb 19, 2024 at 9:08 Nick Cox 35k 6 31 47 answered Feb 19, 2024 at 9:06 cc88 127 11 This isn't the best solution. WebMar 30, 2014 · 1 I would like to replace and retain the original variable name after using the encode command for a set of variables x1-xn. This is where I've started: for var x*: encode x*, generate (x*_) label (label) My question is: what is a clean way to drop the x* (original string) variables?
Introduction to Stata: Creating and Changing Variables
Weba) Look at the nlsw88dates2 data set. Which variables look like dates, but are currently string variables? Change these to Stata date format. b) Now create a stata date … WebApr 26, 2024 · The first bit replaces the label of the variables with the variable label, which should be in the first row of your imported dataset. The second bit drops this row, and the destrings all variables for which this is possible without an error. how to size ductwork
How can I quickly convert many string variables to numeric …
WebMay 27, 2024 · The syntax is just destring variable, replace, where variable should be replaced by the name of the variable (or variables) to be destringed. If the string … WebNov 22, 2024 · replace var1 = subinstr (var1, "- ", "-",.) split var1, generate (x) destring force egen y = ends (var1) if strmatch (var1,"*/*"), last split y, destring force p ("/") replace x1 = cond (x1<0, x1-y1/y2, cond (x1!=.,x1+y1/y2, y1/y2)) if y1!=. keep var1 x1 Share Improve this answer Follow answered Nov 24, 2024 at 1:57 Romalpa Akzo 567 1 4 12 WebFeb 28, 2024 · SIN MOVIMIENTO_2024_01, replace factor-variable and time-series operators not allowed. You have included the character ".", which can't be in the name of … nova rambler how to remove